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4x^2-54x=-176
We move all terms to the left:
4x^2-54x-(-176)=0
We add all the numbers together, and all the variables
4x^2-54x+176=0
a = 4; b = -54; c = +176;
Δ = b2-4ac
Δ = -542-4·4·176
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-10}{2*4}=\frac{44}{8} =5+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+10}{2*4}=\frac{64}{8} =8 $
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